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21x^2-25x-144=0
a = 21; b = -25; c = -144;
Δ = b2-4ac
Δ = -252-4·21·(-144)
Δ = 12721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-\sqrt{12721}}{2*21}=\frac{25-\sqrt{12721}}{42} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+\sqrt{12721}}{2*21}=\frac{25+\sqrt{12721}}{42} $
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